Is there an easy way (without listing them all separately) in jquery to select all form elements and only form elements.
I can’t use children() etc because the form contains other HTML.
E.g:
$("form").each(function(){
let $inputs = $("input, textarea, select", this);
});
isherwood
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asked Oct 12, 2012 at 15:41
John MagnoliaJohn Magnolia
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0
Edit: As pointed out in comments (Mario Awad & Brock Hensley), use .find
to get the children
$("form").each(function(){
$(this).find(':input') //<-- Should return all input elements in that specific form.
});
forms also have an elements collection, sometimes this differs from children such as when the form tag is in a table and is not closed.
May be :input selector is what you want
$(«form»).each(function(){
$(‘:input’, this)//<— Should return all input elements in that specific form.
});
As pointed out in docs
To achieve the best performance when using :input to select elements, first select the elements using a pure CSS selector, then use .filter(«:input»).
You can use like below,
$("form").each(function(){
$(this).filter(':input') //<-- Should return all input elements in that specific form.
});
answered Oct 12, 2012 at 15:43
7
The below code helps to get the details of elements from the specific form with the form id,
$('#formId input, #formId select').each(
function(index){
var input = $(this);
alert('Type: ' + input.attr('type') + 'Name: ' + input.attr('name') + 'Value: ' + input.val());
}
);
The below code helps to get the details of elements from all the forms which are place in the loading page,
$('form input, form select').each(
function(index){
var input = $(this);
alert('Type: ' + input.attr('type') + 'Name: ' + input.attr('name') + 'Value: ' + input.val());
}
);
The below code helps to get the details of elements which are place in the loading page even when the element is not place inside the tag,
$('input, select').each(
function(index){
var input = $(this);
alert('Type: ' + input.attr('type') + 'Name: ' + input.attr('name') + 'Value: ' + input.val());
}
);
NOTE: We add the more element tag name what we need in the object list like as below,
Example: to get name of attribute "textarea",
$('input, select, textarea').each(
function(index){
var input = $(this);
alert('Type: ' + input.attr('type') + 'Name: ' + input.attr('name') + 'Value: ' + input.val());
}
);
tibi
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answered Sep 19, 2013 at 9:50
Srinivasan.SSrinivasan.S
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2
If you have additional types, edit the selector:
var formElements = new Array();
$("form :input").each(function(){
formElements.push($(this));
});
All form elements are now in the array formElements.
answered Oct 12, 2012 at 15:44
JQuery serialize function makes it pretty easy to get all form elements.
Demo: http://jsfiddle.net/55xnJ/2/
$("form").serialize(); //get all form elements at once
//result would be like this:
single=Single&multiple=Multiple&multiple=Multiple3&check=check2&radio=radio1
To compound on that idea: you can use something like this to make all form elements accessible.
Data = $('form').serialize().split('&');
for(i in Data){
Data[i] = Data[i].split('=');
Fields[ Data[i][0] ] = [ Data[i][1],
$('form *[name="' + Data[i][0] + '"]').eq(0) ];
}
console.log(Fields);
// The result would be a multi-dimensional array you could loop through
Fields[Field_Name] = [Field_Value, Field_Object]
Note: This will only work with named fields as serialize() will ignore all others. Any fields with duplicate names will be ignored. You could make a multi-dimensional array if multiple fields use the same name.
TibTibs
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answered Apr 22, 2019 at 9:25
jQuery keeps a reference to the vanilla JS form element, and this contains a reference to all of the form’s child elements. You could simply grab the reference and proceed forward:
var someForm = $('#SomeForm');
$.each(someForm[0].elements, function(index, elem){
//Do something here.
});
answered Mar 9, 2014 at 23:45
Ron Sims IIRon Sims II
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1
For the record: The following snippet can help you to get details about input, textarea, select, button, a tags through a temp title when hover them.
$( 'body' ).on( 'mouseover', 'input, textarea, select, button, a', function() {
var $tag = $( this );
var $form = $tag.closest( 'form' );
var title = this.title;
var id = this.id;
var name = this.name;
var value = this.value;
var type = this.type;
var cls = this.className;
var tagName = this.tagName;
var options = [];
var hidden = [];
var formDetails = '';
if ( $form.length ) {
$form.find( ':input[type="hidden"]' ).each( function( index, el ) {
hidden.push( "t" + el.name + ' = ' + el.value );
} );
var formName = $form.prop( 'name' );
var formTitle = $form.prop( 'title' );
var formId = $form.prop( 'id' );
var formClass = $form.prop( 'class' );
formDetails +=
"nnFORM NAME: " + formName +
"nFORM TITLE: " + formTitle +
"nFORM ID: " + formId +
"nFORM CLASS: " + formClass +
"nFORM HIDDEN INPUT:n" + hidden.join( "n" );
}
var tempTitle =
"TAG: " + tagName +
"nTITLE: " + title +
"nID: " + id +
"nCLASS: " + cls;
if ( 'SELECT' === tagName ) {
$tag.find( 'option' ).each( function( index, el ) {
options.push( el.value );
} );
tempTitle +=
"nNAME: " + name +
"nVALUE: " + value +
"nTYPE: " + type +
"nSELECT OPTIONS:nt" + options;
} else if ( 'A' === tagName ) {
tempTitle +=
"nHTML: " + $tag.html();
} else {
tempTitle +=
"nNAME: " + name +
"nVALUE: " + value +
"nTYPE: " + type;
}
tempTitle += formDetails;
$tag.prop( 'title', tempTitle );
$tag.on( 'mouseout', function() {
$tag.prop( 'title', title );
} )
} );
answered Jul 26, 2015 at 15:43
Igor ParraIgor Parra
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1
This is my favorite function and it works like a charm for me!
It returns an object with all for input, select and textarea data.
And it’s trying to getting objects name by look for elements name else Id else class.
var form_data = get_form_data();
console.log(form_data);
Function:
function get_form_data(element){
element = element || '';
var all_page_data = {};
var all_forms_data_temp = {};
if(!element){
element = 'body';
}
if($(element)[0] == undefined){
return null;
}
$(element).find('input,select,textarea').each(function(i){
all_forms_data_temp[i] = $(this);
});
$.each(all_forms_data_temp,function(){
var input = $(this);
var element_name;
var element_value;
if((input.attr('type') == 'submit') || (input.attr('type') == 'button')){
return true;
}
if((input.attr('name') !== undefined) && (input.attr('name') != '')){
element_name = input.attr('name').trim();
} else if((input.attr('id') !== undefined) && (input.attr('id') != '')){
element_name = input.attr('id').trim();
} else if((input.attr('class') !== undefined) && (input.attr('class') != '')){
element_name = input.attr('class').trim();
}
if(input.val() !== undefined){
if(input.attr('type') == 'checkbox'){
element_value = input.parent().find('input[name="'+element_name+'"]:checked').val();
} else if((input.attr('type') == 'radio')){
element_value = $('input[name="'+element_name+'"]:checked',element).val();
} else {
element_value = input.val();
}
} else if(input.text() != undefined){
element_value = input.text();
}
if(element_value === undefined){
element_value = '';
}
if(element_name !== undefined){
var element_array = new Array();
if(element_name.indexOf(' ') !== -1){
element_array = element_name.split(/(s+)/);
} else {
element_array.push(element_name);
}
$.each(element_array,function(index, name){
name = name.trim();
if(name != ''){
all_page_data[name] = element_value;
}
});
}
});
return all_page_data;
}
answered Jun 10, 2017 at 21:10
2
var $form_elements = $("#form_id").find(":input");
All the elements including the submit-button are now in the variable $form_elements.
answered Jun 29, 2013 at 13:17
1
Just to add another way:
$('form[name=' + formName + ']').find(':input')
answered May 11, 2015 at 13:09
Try this function
function fieldsValidations(element) {
var isFilled = true;
var fields = $("#"+element)
.find("select, textarea, input").serializeArray();
$.each(fields, function(i, field) {
if (!field.value){
isFilled = false;
return false;
}
});
return isFilled;
}
And use it as
$("#submit").click(function () {
if(fieldsValidations('initiate')){
$("#submit").html("<i class="fas fa-circle-notch fa-spin"></i>");
}
});
Enjoy
answered Oct 15, 2019 at 18:12
I used this way to get all input fields from a certain form:
$("#myForm").find("input").each(function() {
// your stuff goes here
});
Or for the case here:
$("#myForm").find("select, textarea, input").each(function() {
// your stuff goes here
});
answered Nov 16, 2021 at 10:31
MarcoMarco
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Years later…
const formElements = Object.entries($('form').get(0).elements)
.reduce((arr, [_, el]) =>
el.name
? Object.assign(arr, { [el.name]: el.value })
: arr,
{}
);
The result is a simple key:value list of all form elements with a non-empty name.
For vanilla JS, replace $('form').get(0)
with simple document.querySelector('form')
.
answered Mar 4 at 17:12
Try something like this:
<form action="/" id="searchForm">
<input type="text" name="s" placeholder="Search...">
<input type="submit" value="Search">
</form>
<!-- the result of the search will be rendered inside this div -->
<div id="result"></div>
<script>
// Attach a submit handler to the form
$( "#searchForm" ).submit(function( event ) {
// Stop form from submitting normally
event.preventDefault();
// Get some values from elements on the page:
var $form = $( this ),
term = $form.find( "input[name='s']" ).val(),
url = $form.attr( "action" );
// Send the data using post
var posting = $.post( url, { s: term } );
// Put the results in a div
posting.done(function( data ) {
var content = $( data ).find( "#content" );
$( "#result" ).empty().append( content );
});
});
</script>
Note the use of input[]
answered Oct 29, 2018 at 3:41
1
all inputs:
var inputs = $("#formId :input");
all buttons
var button = $("#formId :button")
answered Nov 11, 2018 at 20:35
D.L.MAND.L.MAN
97012 silver badges17 bronze badges
jquery isn’t needed.
html control elements must be one of the following:
button
,fieldset
,input
,object
,output
,select
,textarea
so you can use JavaScript’s native querySelectorAll
// use query selector instead
const nodes = document.querySelectorAll(
":where(button,fieldset,input,object,output,select,textarea)"
);
console.log({ nodes });
<div>
<input type="text" id="name" name="name" value="bob">
</div>
<div>
<textarea name="textarea" rows="10" cols="50">Write something here</textarea>
</div>
the above would select form control elements anywhere on the page (even outside of <form>
tags). if you already have the form, and just want those elements, you could just use the elements property for the form:
const formControls = myForm.elements
answered May 1 at 18:14
bristwebbristweb
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jQuery. Как выбрать все input type text
12 мая 2016 18:05
Просмотров: 3879
Jquery selector input[type=text]
Выборка 1 способ
$('.sys input[type=text], .sys select').each(function() {...})
Выборка 2 способ
$('.sys').find('input[type=text],select').each(function() {...})
Выборка 3 способ
$('input[type=text],select', '.sys').each(function() {...})
SkeitOl
Комментарии: 1
Object of all the inputs:-
$("form#formId :input").each(function(){
var input = $(this); // A jquery object of the input
});
or
$('#formId').submit(function() {
// get the array of all the inputs
var $inputs = $('#formId :input');
// get an associative array of the values
var values = {};
$inputs.each(function() {
values[this.name] = $(this).val();
});
});
This one returns the Key:Value
pair —
var values = {};
$.each($('#formId').serializeArray(), function(i, field) {
values[field.name] = field.value;
});
jQuery селекторы
Определение и применение
jQuery селектор :input выбирает все элементы <input> (пользовательское поле для ввода информации), <textarea> (поле формы для создания области многострочного ввода), <select> (раскрывающийся (выпадающий) список) и <button> (используется для размещения кнопки).
jQuery синтаксис:
$(":input")
Добавлен в версии jQuery
1.0
Селектор в CSS
Это селектор jQuery, он не является частью спецификации CSS.
Пример использования
<!DOCTYPE html> <html> <head> <title>Использование jQuery селектора :input.</title> <script src = "https://ajax.googleapis.com/ajax/libs/jquery/3.1.0/jquery.min.js"></script> <script> $(document).ready(function(){ $(":input").css("border", "1px solid orange"); // выбираем все элементы <input>, <textarea>, <select> и <button> в документе }); </script> </head> <body> <form> <select required> <!-- указываем, что элемент раскрывающегося списка должен быть выбран перед отправкой формы --> <option></option> <option>М</option> <option>Ж</option> </select> <input type = "text" placeholder = "Ваше имя"><br><br> <!-- однострочное текстовое поле --> <textarea placeholder = "О себе"></textarea><br> <!-- область многострочного ввода--> <button>Отправить</button> <!-- кнопка --> </form> </body> </html>
В этом примере с использованием селектора :input мы выбрали и стилизовали все элементы <input>, <textarea>, <select> и <button> в документе.
Результат нашего примера:
Skip to content
The jQuery :input selector selects all the input type elements in a form. It selects every input elements including textarea, select box, and button. This can be useful when you want to select the input form elements.
Syntax of the Selector
The syntax of jQuery :input selector is given below.
The above syntax requires no arguments to pass to the selector. However, if you want to select only the specific input element. You have to use the tag name. Suppose, if you want to select only the select box. You have to specify the tag name select before the selector. You have to use the selector as $("select:input")
.
jQuery :input Selector Select All Types of Input Elements
When you want to select the form elements which are using for user inputs. You have to use this selector. It selects every element in a form including the button element. See the example below the selector selects each and every form elements.
Example
Test it Live
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 |
<script> $(document).ready(function(){ $( «.mydforminput :input» ).css(«background», «yellow»); }); </script> <form action=«#» class=«mydforminput»> <label>Name</label> <input type=«text» name=«name» placeholder=«Enter your name…»><br><br> <label>Email</label> <input type=«email» name=«email» placeholder=«Enter your email…»><br><br> <label>Select Your Country</label> <select name=«country»> <option value=«»>Select option</option> <option value=«India»>India</option> <option value=«Australia»>Australia</option> <option value=«USA»>USA</option> <option value=«Germany»>Germany</option> </select><br><br> <button type=«button» name=«submit»>Submit</button> </form> |
Output
The above example showing all the selected form elements with the button element. The selector selects the input, select box, and button elements to apply the background color. It adds a ‘yellow’ color to each and every form elements to highlight them
If you have any queries regarding this tutorial post, please comment below.
Also tell me, what other methods you are using with the selector by commenting below.
References
- jQuery Support Docs
- W3schools Tutorial