Как найти размер файла java

For Java 8 this is one right way to do it:

Files.walk(new File("D:/temp").toPath())
                .map(f -> f.toFile())
                .filter(f -> f.isFile())
                .mapToLong(f -> f.length()).sum()

It is important to filter out all directories, because the length method isn’t guaranteed to be 0 for directories.

At least this code delivers the same size information like Windows Explorer itself does.

answered Feb 21, 2017 at 14:04

Here’s the best way to get a general File’s size (works for directory and non-directory):

public static long getSize(File file) {
    long size;
    if (file.isDirectory()) {
        size = 0;
        for (File child : file.listFiles()) {
            size += getSize(child);
        }
    } else {
        size = file.length();
    }
    return size;
}

Edit: Note that this is probably going to be a time-consuming operation. Don’t run it on the UI thread.

Also, here (taken from https://stackoverflow.com/a/5599842/1696171) is a nice way to get a user-readable String from the long returned:

public static String getReadableSize(long size) {
    if(size <= 0) return "0";
    final String[] units = new String[] { "B", "KB", "MB", "GB", "TB" };
    int digitGroups = (int) (Math.log10(size)/Math.log10(1024));
    return new DecimalFormat("#,##0.#").format(size/Math.pow(1024, digitGroups))
            + " " + units[digitGroups];
}

File.length() (Javadoc).

Note that this doesn’t work for directories, or is not guaranteed to work.

For a directory, what do you want? If it’s the total size of all files underneath it, you can recursively walk children using File.list() and File.isDirectory() and sum their sizes.

answered Jan 27, 2010 at 19:46

The File object has a length method:

f = new File("your/file/name");
f.length();

answered Jan 27, 2010 at 19:47

If you want to use Java 8 NIO API, the following program will print the size, in bytes, of the directory it is located in.

import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;

public class PathSize {

    public static void main(String[] args) {
        Path path = Paths.get(".");
        long size = calculateSize(path);
        System.out.println(size);
    }

    /**
     * Returns the size, in bytes, of the specified <tt>path</tt>. If the given
     * path is a regular file, trivially its size is returned. Else the path is
     * a directory and its contents are recursively explored, returning the
     * total sum of all files within the directory.
     * <p>
     * If an I/O exception occurs, it is suppressed within this method and
     * <tt>0</tt> is returned as the size of the specified <tt>path</tt>.
     * 
     * @param path path whose size is to be returned
     * @return size of the specified path
     */
    public static long calculateSize(Path path) {
        try {
            if (Files.isRegularFile(path)) {
                return Files.size(path);
            }

            return Files.list(path).mapToLong(PathSize::calculateSize).sum();
        } catch (IOException e) {
            return 0L;
        }
    }

}

The calculateSize method is universal for Path objects, so it also works for files.
Note that if a file or directory is inaccessible, in this case the returned size of the path object will be 0.

answered Mar 4, 2017 at 18:18

• Works for Android and Java
• Works for both folders and files
• Checks for null pointer everywhere where needed
• Ignores symbolic link aka shortcuts
• Production ready!

Source code:

   public long fileSize(File root) {
        if(root == null){
            return 0;
        }
        if(root.isFile()){
            return root.length();
        }
        try {
            if(isSymlink(root)){
                return 0;
            }
        } catch (IOException e) {
            e.printStackTrace();
            return 0;
        }

        long length = 0;
        File[] files = root.listFiles();
        if(files == null){
            return 0;
        }
        for (File file : files) {
            length += fileSize(file);
        }

        return length;
    }

    private static boolean isSymlink(File file) throws IOException {
        File canon;
        if (file.getParent() == null) {
            canon = file;
        } else {
            File canonDir = file.getParentFile().getCanonicalFile();
            canon = new File(canonDir, file.getName());
        }
        return !canon.getCanonicalFile().equals(canon.getAbsoluteFile());
    }

answered Oct 15, 2017 at 15:15

I’ve tested du -c <folderpath> and is 2x faster than nio.Files or recursion

private static long getFolderSize(File folder){
  if (folder != null && folder.exists() && folder.canRead()){
    try {
      Process p = new ProcessBuilder("du","-c",folder.getAbsolutePath()).start();
      BufferedReader r = new BufferedReader(new InputStreamReader(p.getInputStream()));
      String total = "";
      for (String line; null != (line = r.readLine());)
        total = line;
      r.close();
      p.waitFor();
      if (total.length() > 0 && total.endsWith("total"))
        return Long.parseLong(total.split("\s+")[0]) * 1024;
    } catch (Exception ex) {
      ex.printStackTrace();
    }
  }
  return -1;
}

answered May 10, 2020 at 19:11

for windows, using java.io this reccursive function is useful.

    public static long folderSize(File directory) {
    long length = 0;

    if (directory.isFile())
         length += directory.length();
    else{
        for (File file : directory.listFiles()) {
             if (file.isFile())
                 length += file.length();
             else
                 length += folderSize(file);
        }
    }

    return length;
}

This is tested and working properly on my end.

answered Jul 17, 2019 at 11:30

public long folderSize (String directory)
    {
        File curDir = new File(directory);
        long length = 0;
        for(File f : curDir.listFiles())
        {
            if(f.isDirectory())
            {               
                 for ( File child : f.listFiles()) 
                 {
                     length = length + child.length();
                 }

                System.out.println("Directory: " + f.getName() + " " + length + "kb");
            }
            else
            {
                length = f.length();
                System.out.println("File: " + f.getName() + " " + length + "kb");
            }
            length = 0;
        }
        return length;
    }

answered Oct 5, 2014 at 18:49

After lot of researching and looking into different solutions proposed here at StackOverflow. I finally decided to write my own solution. My purpose is to have no-throw mechanism because I don’t want to crash if the API is unable to fetch the folder size. This method is not suitable for mult-threaded scenario.

First of all I want to check for valid directories while traversing down the file system tree.

private static boolean isValidDir(File dir){
    if (dir != null && dir.exists() && dir.isDirectory()){
        return true;
    }else{
        return false;
    }
}

Second I do not want my recursive call to go into symlinks (softlinks) and include the size in total aggregate.

public static boolean isSymlink(File file) throws IOException {
    File canon;
    if (file.getParent() == null) {
        canon = file;
    } else {
        canon = new File(file.getParentFile().getCanonicalFile(),
                file.getName());
    }
    return !canon.getCanonicalFile().equals(canon.getAbsoluteFile());
}

Finally my recursion based implementation to fetch the size of the specified directory. Notice the null check for dir.listFiles(). According to javadoc there is a possibility that this method can return null.

public static long getDirSize(File dir){
    if (!isValidDir(dir))
        return 0L;
    File[] files = dir.listFiles();
    //Guard for null pointer exception on files
    if (files == null){
        return 0L;
    }else{
        long size = 0L;
        for(File file : files){
            if (file.isFile()){
                size += file.length();
            }else{
                try{
                    if (!isSymlink(file)) size += getDirSize(file);
                }catch (IOException ioe){
                    //digest exception
                }
            }
        }
        return size;
    }
}

Some cream on the cake, the API to get the size of the list Files (might be all of files and folder under root).

public static long getDirSize(List<File> files){
    long size = 0L;
    for(File file : files){
        if (file.isDirectory()){
            size += getDirSize(file);
        } else {
            size += file.length();
        }
    }
    return size;
}

answered Jan 21, 2017 at 16:23

answered Mar 31, 2017 at 19:27

You can use Apache Commons IO to find the folder size easily.

If you are on maven, please add the following dependency in your pom.xml file.

<!-- https://mvnrepository.com/artifact/commons-io/commons-io -->
<dependency>
    <groupId>commons-io</groupId>
    <artifactId>commons-io</artifactId>
    <version>2.6</version>
</dependency>

If not a fan of Maven, download the following jar and add it to the class path.

https://repo1.maven.org/maven2/commons-io/commons-io/2.6/commons-io-2.6.jar

public long getFolderSize() {

    File folder = new File("src/test/resources");
    long size = FileUtils.sizeOfDirectory(folder);

    return size; // in bytes
}

To get file size via Commons IO,

File file = new File("ADD YOUR PATH TO FILE");

long fileSize = FileUtils.sizeOf(file);

System.out.println(fileSize); // bytes

It is also achievable via Google Guava

For Maven, add the following:

<!-- https://mvnrepository.com/artifact/com.google.guava/guava -->
<dependency>
    <groupId>com.google.guava</groupId>
    <artifactId>guava</artifactId>
    <version>28.1-jre</version>
</dependency>

If not using Maven, add the following to class path

https://repo1.maven.org/maven2/com/google/guava/guava/28.1-jre/guava-28.1-jre.jar

public long getFolderSizeViaGuava() {
        File folder = new File("src/test/resources");
        Iterable<File> files = Files.fileTreeTraverser()
                .breadthFirstTraversal(folder);
        long size = StreamSupport.stream(files.spliterator(), false)
                .filter(f -> f.isFile())
                .mapToLong(File::length).sum();

        return  size;
    }

To get file size,

 File file = new File("PATH TO YOUR FILE");
 long s  = file.length();
 System.out.println(s);

answered Nov 11, 2019 at 1:52

fun getSize(context: Context, uri: Uri?): Float? {
    var fileSize: String? = null
    val cursor: Cursor? = context.contentResolver
        .query(uri!!, null, null, null, null, null)
    try {
        if (cursor != null && cursor.moveToFirst()) {

            // get file size
            val sizeIndex: Int = cursor.getColumnIndex(OpenableColumns.SIZE)
            if (!cursor.isNull(sizeIndex)) {
                fileSize = cursor.getString(sizeIndex)
            }
        }
    } finally {
        cursor?.close()
    }
    return fileSize!!.toFloat() / (1024 * 1024)
}

answered Dec 23, 2021 at 12:45