Как найти последний четный элемент массива

I want to find the index of the last element containing an even number in an array, A, with ‘length’ number of elements.
For example, for A = {1, 2, 4, 5, 7} we would return 2 as the value 4 is the last even number and it is at index 2 in the array.
I am required to use a for loop where the fewest number of elements need to be tested, where the first line follows the format:
for ( i = ??; i > ??; i = ??)

I think there’s something wrong with the first line of my code but I don’t know how to fix it.

for ( i = length-1; i >= 0; i =  i-1) { 
if ( A[i] % 2 == 0) { // value mod 2 = 0 indicates even
    return i;
}

error: subscripted value is neither array nor pointer nor vector
     'if (A[i]% 2==0) { // value mod 2 = 0 indicates even'

Here is how I would write it:

int num = -1;
for ( i = length-1; i > -1; i = i-1) {
  //Check if the array is even
  if( A[i] % 2 == 0 )

    // If it hasn't found an even number yet, automatically set num equal to the index
    // This avoids accessing the element in the "-1" position in the array which would
    //    give an error
    if( num == -1 )
      num = i;

    // If the element at the 'i' position is greater than the previous greatest element
    //   then set num equal to the index
    else if( A[i] > A[num] )
      num = i;
}

// It will return -1 if an even number isn't found
return num;

This will work if A is an array. It sounds like A currently isn’t the array you’re thinking it is; it may be an array of arrays or something similar. If you post the rest of your code it will help to resolve the error.

This answer may help you with your error

answered May 16, 2019 at 12:27